Relate the strengths of a conjugate acid and base in water.
Difficulty
Beginner
Read time
3 min
Prerequisites
Basic algebra and molar quantities
Source
OpenStax, Chemistry 2e, §14.3Adapted from Teng-Jui Lin’s CHEM 155 equation sheet. The linked textbook reference was used to check the equation and its physical context. Pending editorial review.
Adapted from Teng-Jui Lin, Equation Sheets, under CC BY 4.0.
FormuLab adapted notation and chemical symbols, added variable meanings, units, applicability conditions, and an original worked example.
A conjugate acid’s K_a and its conjugate base’s K_b multiply to the water ion-product constant at the same temperature. A larger K_a therefore corresponds to a smaller conjugate-base K_b.
| Symbol | Meaning | Units |
|---|---|---|
| Dimensionless dissociation constant of the conjugate acid | ||
| Dimensionless dissociation constant of its conjugate base | ||
| Dimensionless water ion-product constant at the same temperature |
Calculate a base constant from its conjugate acid constant.
Compare linked acid and base equilibria.
At 25 °C, an acid has K_a = 1.80 × 10⁻⁵. Using K_w = 1.00 × 10⁻¹⁴, find its conjugate base’s K_b.
Adapted from Teng-Jui Lin’s CHEM 155 equation sheet. The linked textbook reference was used to check the equation and its physical context. Pending editorial review.
Adapted from Teng-Jui Lin, Equation Sheets, under CC BY 4.0.
FormuLab adapted notation and chemical symbols, added variable meanings, units, applicability conditions, and an original worked example.
Assumptions
FormuLab is a study reference. Verify formulas, units, assumptions, and course-specific conventions before relying on them.
© 2026 FormuLab. All rights reserved.