Thermodynamics

Ideal-Gas Specific Internal Energy Change

Calculate a mass-specific property change from temperature change and a constant heat capacity.

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Calculate change in mass-specific internal energy or choose another supported quantity.

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Use decimals or scientific notation, such as 1.2e3. Calculations update as you type.

Change in mass-specific internal energy

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Use an ideal gas with the stated specific heat approximately constant over the temperature interval. Use a mass-specific heat capacity for a result in J/kg. For an ideal gas, this property change depends on temperature alone; the actual path need not have constant volume. Heat transferred is not generally equal to this property change; account for work and flow terms separately.

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Source & review

Difficulty

Intermediate

Read time

5 min

Prerequisites

Basic algebra and introductory thermodynamics

Review statusNeeds review

Source

Teng-Jui Lin — CHEM E 326 — Chemical Engineering Thermodynamics

Reference equation: Measurable properties — Constant volume heat capacity. FormuLab wrote new explanations, assumptions, applications, and numerical examples. Integrated the ideal-gas property derivative with constant mass-specific heat capacity; did not equate property change with process heat.

Adapted from Teng-Jui Lin, Equation Sheets — Mechanical Engineering Expansion, under CC BY 4.0.

Adapted standard equations and added original lesson text, variables, SI examples, and assumptions. Integrated the ideal-gas property derivative with constant mass-specific heat capacity; did not equate property change with process heat.

Definition

Understanding the core concept

An ideal gas’s internal energy depends only on temperature. With a constant mass-specific heat capacity, integrating its temperature derivative gives a property change proportional to the temperature difference.

Variables & Units

Understanding each component
SymbolMeaningUnits
Change in mass-specific internal energy
Mass-specific heat capacity at constant volume
Final absolute temperature
Initial absolute temperature

Real-World Applications

Where this formula is used in practice

Gas property changes

Estimate an ideal-gas property difference.

Energy balances

Supply a property change while treating process heat and work separately.

Worked Example

Step-by-step calculation with real numbers

Problem

An ideal gas has cv = 718 J/(kg·K) and warms from 300 K to 400 K. Find its specific property change.

Given

Solution

1
2

Final Answer

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