FormuLab
Thermodynamics

Vapor-Compression Refrigeration COP

A refrigerator's coefficient of performance compares useful evaporator cooling with compressor work input.

Study tools
Save, share, export, or report this formula.
Source & review

Difficulty

Intermediate

Read time

4 min

Prerequisites

Consistent SI units, algebra, and the physical assumptions listed below

Review statusNeeds review

Source

Teng-Jui Lin — Equation Sheets

Adapted from Teng-Jui Lin, Equation Sheets — Mechanical Engineering, under CC BY 4.0.

Adapted notation and added original explanations, variables, assumptions, applications, and a worked example. Renumbered the states to the standard compressor 1→2 convention used in FormuLab's concept lesson.

Definition
Understanding the core concept

A refrigerator's coefficient of performance compares useful evaporator cooling with compressor work input. A COP greater than one is normal because work moves heat rather than creating all of the cooling energy directly.

Variables & Units
Understanding each component
SymbolMeaningUnits
Refrigeration coefficient of performance
Specific enthalpy at evaporator exit / compressor inlet
Specific enthalpy at compressor exit / condenser inlet
Specific enthalpy at valve exit / evaporator inlet
Real-World Applications
Where this formula is used in practice

Refrigeration analysis

Evaluate a four-state vapor-compression cycle.

Performance interpretation

Distinguish cooling COP from heat-engine efficiency.

Worked Example
Step-by-step calculation with real numbers

Problem

For illustrative refrigerant enthalpies h₁ = 400, h₂ = 440, and h₄ = 250 kJ/kg, find the refrigeration COP.

Given

Solution

1
2

Final Answer

FormuLab is a study reference. Verify formulas, units, assumptions, and course-specific conventions before relying on them.

Browse by category

See all